I’ve got a few e-mails regarding the 7-5 vs. 6-6 rule in terms of bowl berths. I checked again with Cal and the Pac-10 office, and they reiterated: Yes, a 7-5 team gets the nod over a 6-6 team to qualify for a bowl berth. But once all the berths within a conference have been awarded — in other words, if there are enough bids to go around for all teams eligible — then bowl bids are still handed out in the order of the conference standings. So UCLA still is ahead of Cal even if the Bears win tomorrow to finish 7-5.

Now, if Arizona beats Arizona State and Cal beats Stanford, either the Wildcats or the Bruins will be left out of a Pac-10 bowl game because by rule the Bears will get a bid over one of the teams. Cal would be the fifth team in from the conference, with one spot left between Arizona and UCLA. The bowl would get to pick between the two schools. And once that team is picked, they would automatically be ahead of Cal in the conference standings. Thus, in that scenario, the Bears would be headed to the Armed Forces Bowl.

Got all that? Yeah, I’m thinking the same thing. Let’s just wait until after the games are played tomorrow and have somebody tell us what’s going on!

Jonathan Okanes

Jonathan Okanes is in his fourth year covering Cal's football team. Previously, he covered Cal's men's basketball team for four years. He can also be followed on Twitter at twitter.com/OkanesonCal.

  • MattC

    The bowl bids aren’t automatically handed out in order of conference standings; the bowls are given their choice (except the Rose Bowl, which might be contracted to take the conference champion…not that it would do otherwise). So that means the Holiday Bowl gets its choice of all the other Pac-10 bowl eligble teams, then the Sun Bowl, then the Emerald Bowl, then the Las Vegas Bowl…and it’s quite likely the Emerald Bowl would rather take Cal over UCLA, since Cal is closer, and UCLA played there last year.